Chemistry, 18.07.2020 02:01 kcarstensen59070
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is
Answers: 3
![[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4} } = 0.0106 M](/tpl/images/0709/0894/13a06.png)
![\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%](/tpl/images/0709/0894/0f396.png)
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Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The...
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