If 75 kJ of heat is transferred to 1200 g liquid water at 36°C, what would the new temperature of the water be? (The specific heat capacity of liquid water
is 4.186 J/g.°C.)

50.9° (corrected to 3 significant figures)

Explanation:

Energy(J) = mass(kg) x specific heat capacity x temperature change

(E = mcΔT)

Let the new temperature be T.

75000 = (1.2 )(4186)(T-36)

14.930 = T -36

T = 50.9°

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.