A pressure cooker contains 5.68 liters of air at a temperature of 394 K. If the absolute pressure of the air in the pressure cooker is 205 pascals, how many moles of air are in the cooker? The cooker contains moles of air.

The question is incomplete. The value for the absolute pressure of air in the pressure cooker is 205 kilopascals I.e. 205, 000 pascals not 205 pascals.

The answer is n= 0.355 mol

Explanation:

The ideal gas equation will be used to solve this question. The ideal gas equation is:

PV=nRT

Where; P = absolute pressure

(atm)

V = Volume (Litres)

n = no. of moles

R = ideal gas constant

(0.0821 L atm/ mol K)

T = absolute temperature

(K)

According to this question, V= 5.68L, P= 205 Kpa, T= 394K

However, the unit of pressure must be converted to atm

1 atm = 101325pa

Hence, 205000 pa will be 205000/101325 atm

= 2.02 atm

Since, n in the equation PV=nRT is being sought for, we make "n" subject of the formula. Thus, n = PV/RT

n = 2.02 × 5.68 / 0.0821 × 394

n = 11.4736 / 32.3474

n = 0.355 mol

Thus, The pressure cooker contains 0.355 moles of air.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

12 is it do you think so