For reaction: 2 C + O2 --> 2 CO2 If 5.50 g C was reacted with enough O2, what would be the volume (in liter) of the CO2 generated at STP? (0 C and 1 atm)

10.2 L of CO₂

Explanation:

Our reaction is:

2C + O₂  →  2CO₂

We convert the mass of C, to moles:

5.50 g / 12g/mol = 0.458 moles

Ratio is 2:2, so if 2 moles of C can produce 2 moles of CO₂ then 0.458 moles of C would produce 0.458 moles of gas.

By the Ideal Gases Law, we know that 1 mol of gas is contained in 22.4L, so:

0.458 mol . 22.4L / 1mol = 10.2 L

explanation:

0.07 g/cm³

1.37 g/cm³