A 110.0 L weather balloon filled with 4.00 mol of helium has a small leak. If the helium leaks at a rate of 10.0 mmol/hr, what is the volume of the balloon after 38.0 hours

The volume of the balloon after 38.0 hours is 99.55 L

Explanation:

Given;

volume of helium in the weather balloon, V = 110 L

initial mole of the gas, n = 4 mol

the rate leak of the gas, dn/dt = 10 mmol/hr

After 38.0 hours, the moles of the gas lost = 38hr x 10 x 10⁻³ mol/hr = 0.38 mol

the moles of the gas lost = 0.38 mol

Number of moles of helium in balloon after 38.0 hours = 4 mol - 0.38 mol

                                                                                            = 3.62 mol

Volume of helium in balloon after 38.0 hours ;

Therefore, the volume of the balloon after 38.0 hours is 99.55 L

right

explanation:

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890