An aqueous solution is made by dissolving 29.4 grams of aluminum acetate in 433 grams of water. The molality of aluminum acetate in the solution is

0.333 m

Explanation:

Molality (m) is moles of solute over kilograms of solvent.

Convert grams of the solute (aluminum acetate) to moles.

(29.4 g)/(204.11 g/mol) = 0.144 mol

Convert grams of the solvent (water) to kilograms.

433 g = 0.433 kg

Divide the solute by the solvent.

(0.144 mol)/(0.433 kg) = 0.333 m

The molality of the solution is 0.333 m.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l