Pb2+(aq) + 2 e- --> Pb(s) Eo = -0.13V Zn2+(aq) + 2 e- --> Zn(s) Eo = -0.76V 9. Given the half-cell potentials above, when the reaction Zn(s) + Pb2+(aq) --> Zn2+(aq) + Pb(s) is made into a voltaic cell, the Ecell is: A. 0.63 V B. -0.63 V C. 0.89 D. 0.89

The is 0.63 V

Explanation:

In the given reaction :

Here Zn undergoes oxidation by loss of electrons, thus act as anode. Lead undergoes reduction by gain of electrons and thus act as cathode.

Where both are standard reduction potentials.

Thus the is 0.63 V

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.

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