What is the balanced oxidation half-reaction for the following reaction? Cu2+(aq) + Fe(s) → Cu(s) + Fe2+(aq) Question 8 options: There is no reaction Cu2+(aq) + 2e– → Cu(s) Fe2+(aq) + 2e– → Fe(s) Cu(s) → Cu2+(aq) + 2e– Fe(s) → Fe2+(aq) + 2e–

Fe(s) → Fe2+(aq) + 2e-

Explanation:

Cu2+(aq) + Fe(s) → Cu(s) + Fe2+(aq)

Oxidation is the loss of electrons. When the oxidation number of an element increases, that means there is a loss of electrons and that element is being oxidized.

The oxidation half equation in this reaction is;

Fe(s) → Fe2+(aq)

The loss of electron is represented in the product side and is given by;

Fe(s) → Fe2+(aq) + 2e-