Chemistry, 27.07.2020 01:01 aprilreneeclaroxob0c

since Ag and Cl are in equilibrium with AgCl, find Ksp for agcl from the concentrations. Write the expression for ksp AgCl and determine its value

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Answer from: mmxotwod

When Ag⁺ and Cl⁻ are in equilibrium with AgCl, the expression for Ksp is

$Ksp = [Ag^{+} ][Cl^{+} ]$

And its value is 1.77 × 10⁻¹⁰.

Let's consider the equation for the solution of AgCl.

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

The molar solubility of AgCl (S) at 25 °C is 1.33 × 10⁻⁵ M. We can use this information to calculate the solubility product (Ksp) through an ICE chart.

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I 0 0

C +S +S

E S S

The solubility product (Ksp) for AgCl is:

$Ksp = [Ag^{+} ][Cl^{+} ] = S.S = S^{2} = (1.33 \times 10^{-5} )^{2} = 1.77 \times 10^{-10}$

When Ag⁺ and Cl⁻ are in equilibrium with AgCl, the expression for Ksp is

$Ksp = [Ag^{+} ][Cl^{+} ]$

And its value is 1.77 × 10⁻¹⁰.

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Answer from: j1theking18

1.69 ×10^-10

Explanation:

Given that the equation for the dissolution of AgCl in water is;

AgCl(s) ⇄Ag^+(aq) + Cl^+(aq)

Also, silver ion and chloride ion are in equilibrium with the undissociated AgCl hence we can write;

Ksp= [Ag+][Cl-]/ [AgCl]

Since the activity of the pure sold is 1, we now have;Ksp= [Ag+][Cl-]

If we know the solubility of AgCl in pure water to be 1.3 x 10^-5 M, from standard tables, and [Ag+]=[Cl-]= 1.3 x 10^-5 M = x

Then;

Ksp= x^2

Ksp= (1.3 x 10^-5)^2

Ksp= 1.69 ×10^-10

Answer from: Quest

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

Answer from: Quest

1 a

2 d

3 a

4 c

explanation:

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since Ag and Cl are in equilibrium with AgCl, find Ksp for agcl from the concentrations. Write the e...