En la reacción química. NaHCO3 + HCl → CO2 + NaCl + H2O Cuando reaccionan 56 g de NaHCO3 los g de CO2 liberados son: Nota: Solo escribir el valor numérico, sin unidades y dos lugares después del punto.

29.34

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:            84.01                                 44.01

             NaHCO₃ +  HCl ⟶ NaCl  +  CO₂  +H₂O

m/g:           56

To solve a stoichiometry problem, you must  use the molar

1. Moles of NaHCO₃

2. Moles of CO₂

The molar ratio is 1 mol CO₂:1 mol NaHCO₃

3. Mass of CO₂

Note: The answer can have only two significant figures because that is all you gave for the mass of NaHCO₃.

ill try to . no promises tho.

explanation: