Which set of numbers gives the correct possible values of l for n = 3? 0, 1, 2 0, 1, 2, 3 –2, –1, 0, 1, 2 –3, –2, –1, 0, 1, 2, 3

0, 1, 2  

Explanation:

The rules for quantum numbers are:

n = 1, 2, 3, 4, …

l = 0, 1, 2, …, n - 1

mₗ = -l, -l + 1, …, 0, …, l - 1, l

If n = 3, l can go from 0 to 3 - 1 = 2.

The correct possible values of l are 0, 1, 2.

B is wrong because the maximum possible value of l is 2.

C and D are wrong because they contain negative numbers. They must be possible sets of magnetic quantum numbers, mₗ.

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