A 223.6 mL of volume of gas is measured at 74.5C. If the pressure remains unchanged, what is the volume of gas at standard temperature? A) 1820 B) 61.02 C) 819.4 D) -307.5

175.7 mL

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 223.6 mL

Initial temperature (T1) = 74.5 °C

Final temperature (T2) = stp = 273 K

Final volume (V2) =.?

Next, we shall convert celsius temperature to Kelvin temperature.

This is illustrated below:

Temperature (K) = Temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 74.5 °C

Initial temperature (T1) = 74.5 °C + 273 = 347.5 K

Finally, we shall determine the volume of the gas at standard temperature as follow:

Initial volume (V1) = 223.6 mL

Initial temperature (T1) = 347.5 K

Final temperature (T2) = stp = 273 K

Final volume (V2) =.?

V1/T1 = V2/T2

223.6/347.5 = V2/273

Cross multiply

347.5 x V2 = 223.6 x 273

Divide both side by 347.5

V2 = (223.6 x 273) /347.5

V2 = 175.7 mL

Therefore, the volume of the gas at standard temperature is 175.7 mL.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

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