The volume of a gas is 8.0 L at 9.9°C and {P3} atm. What volume will the gas occupy if the temperature is raised to 9.3°C at constant pressure?
Select one:
O a. 7.98
Ob.0.263
C. 8.02
O d. 228

Option A. 7.98 L.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 8 L

Initial temperature (T1) = 9.9 °C

Final temperature (T2) = 9.3 °C

Final volume (V2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be achieved as shown below:

Temperature (K) = temperature (°C) + 273

T(K) = T (°C) + 273

Initial temperature (T1) = 9.9 °C

Initial temperature (T1) = 9.9 °C + 273 = 282.9 K

Final temperature (T2) = 9.3 °C

Final temperature (T2) = 9.3 °C + 273 = 282.3 K

Finally, we shall determine the new volume of the gas as follow:

Initial volume (V1) = 8 L

Initial temperature (T1) = 282.9 K

Final temperature (T2) = 282.3 K

Final volume (V2) =..?

V1/T1 = V2/T2

8/282.9 = V2/282.3

Cross multiply

282.9 x V2 = 8 x 282.3

Divide both side by 282.9

V2 = (8 x 282.3)/282.9

V2 = 7.98 L

Therefore, the new volume of the gas is 7.98 L

i dont know the answe

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.