Chromium-51 is a radioactive isotope used to label red blood cells to identify if they remain intact in the body. it has a half-life of 27.7 days. if 0.25 mg is an approximate dose amount, how much remains after 83.1 days?

Amount of chromium-51 remaining after 83.1 days = 0.031 mg

Explanation:

Radioactive disintegration follows the exponential law which can be mathematically expressed as:

where N(0) = initial amount of the radioactive substance

N(t): radioactive substance left after time t

t1/2 = half life of the radioisotope

In the case of chromium-51:

N(0) = 0.25 mg

t = 83.1 days

t1/2 = 27.7 days

Substituting these values in equation (1) gives:

0

explanation:

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