Determine the pressure, in atm, for 3.66 Liters of NH3 gas at a temperature of 298 K and a mass of 10.0 g?

3.92 atm

Explanation:

The formula for the pressure of a gas is P = nRT/V. We have the following:

R - 0.0821 (gas constant)

T - 298 K

V - 3.66 L

n - ? (in moles)

We have to find the moles of the NH₃ gas. To do that, we have to divide the mass of the NH₃ gas by the molar mass of NH₃.

10.0 g × 1 mol NH₃/17.03 g NH₃ = 0.587 moles (rounded to 3 decimal places)

Now we have all the information needed to solve for the pressure.

P = nRT/V

P = (0.587)(0.0821)(298) ÷ 3.66

P = 14.3614246 ÷ 3.66

P = 3.923886503 ⇒ 3.92 atm (rounded to 3 decimal places)

The pressure of the NH₃ gas at a temperature of 298 K and a mass of 10.0 g is 3.92 atm.

Hope that helps.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

well in order to answer this question you have to provide more information < 3