Compound A has molecular formula C7H15Br. Treatment of compound A with sodium ethoxide yields only one elimination product (compound B) and no substitution products. When compound B is treated with dilute sulfuric acid, compound C is obtained, which has molecular formula C7H16O. Draw the structures of compounds A, B, and C. a. Draw compound A
b. Draw compound B
c. Draw compound C
This question has been answered before, but all of the answers were incorrect. Unsure, but there maybe chirality centers that were not in any of the previous answers to this question.