You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes are additive, what is the molarity of chloride ion in the mixture.

Explanation:

Hello,

In this case, since iron (III) chloride (FeCl3) and barium chloride (BaCl2) are both chloride-containing compounds, we can compute the moles of chloride from each salt, considering the concentration and volume of the given solutions, and using the mole ratio that is 1:3 and 1:2 for the compound to chlorine:

So the total mole of chloride ions:

And the total volume by adding the volume of each solution in L:

Finally, the molarity turns out:

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c. is the answer

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