What is the [H+] in a solution with pOH of 0.253? A. 5.58 × 10−15 M B. 1.79 × 10−14 M C. 3.21 × 10−2 M D. 5.58 × 10−1 M

Explanation:

To find [H+] in the solution we must first find the pH

That's

pH = - log[H+]

pH + pOH = 14

pOH = 0.253

pH = 14 - 0.253

pH = 13.747

Since we've found the pH we can now find the [H+] in the solution

We have

pH = - log[H+]

13.747 = - log[H+]

Take antilog of both sides

We have the final answer as

Hope this helps you

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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