Question 6 of 8 > Calculate the standard enthalpy change for the reaction at 25 °C. Standard enthalpy of formation values can be found in this
list of thermodynamic properties.
H2O(g) + C(graphite)(s)
H2(g) + CO(g)
KJ
ΔΗΓκη
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Q
5:24 PM
8/2/2020

131.29 kJ

Explanation:

Let's consider the following balanced equation.

H₂O(g) + C(graphite)(s)  ⇄ H₂(g) + CO(g)

Given the standard enthalpies of formation (ΔH°f), we can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.

ΔH°r = 1 mol × ΔH°f(H₂(g)) + 1 mol × ΔH°f(CO(g)) - 1 mol × ΔH°f(H₂O(g)) - 1 mol × ΔH°f(C(graphite)(s))

ΔH°r = 1 mol × (0 kJ/mol) + 1 mol × (-110.53 kJ/mol) - 1 mol × (-241.82 kJ/mol) - 1 mol × (0 kJ/mol)

ΔH°r = 131.29 kJ

answer; i believe the correct answer is (c) /// is a homogeneous mixture of gaseous substance nitrogen,oxygen and smaller amounts of other substancesmixtures can be either ( homogeneous or heterogeneous)plz check first good luck

it's filtration, but this is an assumption so my apologies if i got this