If the molarity of sugar is 1.1, what will the freezing point be?

The freezing point will be -2.046°C.

Explanation:

The freezing point depression equation is

Where;

= The temperature depression of the freezing point

= The constant of freezing point depression which is solvent dependent = 1.86°C/m

i = The number of particles the substance decomposes into in solution = 1 for sugar (a covalent compound)

m = The molality of the solution = 1.1

Therefore, we have;

Therefore the freezing point will be 0 - 2.046°C = -2.046°C.

3 hours because it is a decent distance.

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.