When NaOH is added to water, the [OH-] = 0.04 M. What is the [H3O+]?

The answer is

Explanation:

To find the [H3O+] in the solution we must first find the pOH and the pH of the solution

That's

pH + pOH = 14

pH = 14 - pOH

To find the pOH we use the formula

pOH = - log [OH-]

[OH-] = 0.04 M

pOH = - log 0.04

So the pH is

pH = 14 - 1.4

So the [H3O+] can be found by

pH = - log [H3O+]

12.6 = - log [H3O+]

Find the antilog of both sides

Hope this helps you

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