Answers: 2
![[OH^-]=1.66x10^{-14}M](/tpl/images/0717/6413/faf0d.png)
![pH=-log([H_3O^+])=-log(0.6M)=0.22](/tpl/images/0717/6413/a7df8.png)
![pOH=-log([OH^-]}\\\\](/tpl/images/0717/6413/83822.png)
![[OH^-]=10^{-pOH]=10^{-13.78}](/tpl/images/0717/6413/27009.png)
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When HCl is added to water, the [H3O+] = 0.6 M. What is the [OH-]?
What is the pH of the solution?...
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