Suppose that in a corrosion cell composed of copper and zinc, the current density at the copper cathode is 0.05 A/cm2 . The area of both the copper and zinc electrodes is 100 cm2 . Calculate (a) the corrosion current, (b) the current density at the zinc anode, and (c) the zinc loss per hour.

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is  2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry  problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that     10 dm = 1 m  ⇔ 10³ dm³ = 1 m³then we use the fact that     10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting:     now we have to find the moles of hydrochloric  acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by    molar mass = (mass ca) + (mass c) + 3(mass o)    = 40 + 12 + 3(16)    = 100 g/molconvert the given 5 g to moles:     mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis    mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃)    = 0.05 mol hcl * 2    = 0.1 mol hcl  we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get     volume = moles / concentration    volume = 0.1 mol / (0.002 mol/cm³)    volume = 50 cm³

The answer to your q it is false

Electricity is conducted when charges move from one place to another. in metals, the conductivity is due to delocalized electrons that can wander all over the place. you're probably already familiar with this.in solid ionic compounds, on the other hand, the ions aren't going anywhere. the cations and anions all attract themselves into a nice lattice and they're stuck there until they have a better reason to wander off. no moving ions = no electricity.however, if you melt an ionic compound or dissolve it in water, these ions are now free to move around. as a result, the solution can be made to conduct electricity.think about this, in solid form the outer shells of the elements are filling each other thus neutralizing the substance, but when you separate the ions (atoms of each element) their shells have space that needs to be filled or emptied, so they want to gain or loose electrons to have a full energy level. because they want this the electrons are able to move and "bounce" from ion to ion.i believe this is correct not 100%