calculate the volume of hydrogen produced at s. t.p when 25g and zinc are added to excess dilute hydrochloric acid at 31 degrees and 778 mm Hg pressure ( H= 1 , Zn = 65 , cl = 35.5 , volume of gas at stop = 22.4 dm cube

The volume of hydrogen gas produced at s.t.p. is 9.419 dm³

Explanation:

The balanced chemical equation for the reaction is given as follows;

Zn + 2HCl → ZnCl₂ + H₂

Therefore, we have;

One mole of Zn reacts with 2 moles of HCl to produce one mole of ZnCl₂ and one mole of H₂

Number of moles of Zn present = 25/65 = 5/13 = 0.385 moles

Therefore, number of moles of H₂ produced = 0.385 moles

The volume of hydrogen gas produced is given by the relation

PV = nRT, we have;

R = 8.3145 J/(mol·K)

V = nRT/P = 0.385 ×8.3145 ×298.15/(101325)= 0.009419 m³ = 9.419 dm³

The volume of hydrogen gas produced at s.t.p. = 9.419 dm³.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.

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