In which list are the three compounds above correctly listed in order of increasing boiling point? A) lowest b. p isopropanol < isobutane < acetone ...highest b. p. B) lowest b. p isobutane < acetone < isopropanol ...highest b. p. C) lowest b. p isobutane < isopropanol < acetone ...highest b. p. D) lowest b. p acetone < isobutane < isopropanol ...highest b. p. E) lowest b. p acetone < isopropanol < isobutane ...highest b. p.

The correct answer is - option B -  lowest b.p isobutane < acetone < isopropanol ...highest b.p.

Explanation:

Isobutane has lowest boiling point due to no hydrogen bonding and no diole to dipole interaction found in them. Isobutane only shows weak dispersion force.

Acetone has dipole dipole interaction but due to lack of Hydrogen bonding they have low boiling point than isopropanol but higher than isobutanol.

Isopropanol is the compound that has ability to form hydrogen bonding with other molecule its boiling point is maximum among all three.

Thus, the correct answer is - option B -  lowest b.p isobutane < acetone < isopropanol ...highest b.p.

sry but any answer choices

c. 75.7

i think that is the right