Chemistry, 14.08.2020 04:01 hiiliohi1018
Consider the ligand field splitting of octahedral and tetrahedral complexes that we discussed in class. Draw the d-orbital splitting for an octahedral and a tetrahedral complex. Copper(I) complexes tend to be tetrahedral rather than octahedral or square planar. Why is this the case? Explain your reasoning. This is the case because Now consider a linear complex with only 2 ligands that lie on the z-axis. If you were to draw the d-orbital splitting for this complex, which orbital(s) would you expect to increase the most (be the highest) in energy? Least? Explain your reasoning
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Consider the ligand field splitting of octahedral and tetrahedral complexes that we discussed in cla...
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