The reaction between lead ion and chloride ion is given below: Pb2+(aq) + 2 Cl-(aq) PbCl2(s)
We therefore know that which of the following reactions can also occur?
a) Pb(s) + Cl2(g) PbCl2(s)
b) PbCl2(s) Pb(s) + Cl2(g)
c) CH4(g) CO(g) + 3 H2(g)
d) None of the Above

43.452

step-by-step explanation:

284 times .153 = 43.452

може ли да зареждате повече информация, моля

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied