Chemistry, 22.08.2020 19:01 stellaglenn205

Chlorine dioxide reacts in basic water to form chlorite and chlorate according to the following chemical equation: 2ClO2(aq) + 2OH−(aq) → ClO−2(aq) + ClO−3(aq) + H2O(l)
Under a certain set of conditions, the initial rate of disappearance of chlorine dioxide was determined to be 2.30 × 10−1 M/s. What is the initial rate of appearance of chlorite ion under those same conditions?

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Answer from: maxg7988

If the initial rate of disappearance of ClO₂ is 2.30 × 10⁻¹ M/s, the rate of appearance of ClO₂⁻ is 1.15 × 10⁻¹ M/s.

Chlorine dioxide reacts in basic water to form chlorite and chlorate according to the following chemical equation:

2 ClO₂(aq) + 2 OH⁻(aq) → ClO₂⁻(aq) + ClO₃⁻(aq) + H₂O(l)

In this problem, we want to find an initial rate of reaction.

What is the rate of reaction?

The rate of reaction is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time.

We can relate the rate of disappearance of ClO₂ and the rate of appearance of ClO₂⁻, using the molar ratios.

What are the molar ratios?

Molar ratios state the proportions of reactants and products that are used and formed in a chemical reaction.

The molar ratio of ClO₂ to ClO₂⁻ is 2:1.

If the initial rate of disappearance of ClO₂ is 2.30 × 10⁻¹ M/s, the rate of appearance of ClO₂⁻ is:

2.30 × 10⁻¹ mol ClO₂/L.s × (1 mol ClO₂⁻/2 mol ClO₂) = 1.15 × 10⁻¹ M/s

If the initial rate of disappearance of ClO₂ is 2.30 × 10⁻¹ M/s, the rate of appearance of ClO₂⁻ is 1.15 × 10⁻¹ M/s.

Learn more about rates of reaction here: link

Answer from: gyexisromero10

The initial rate of appearance of chlorite ion under those same conditions is $
1.15\times 10^{-1}M/s$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2ClO_2(aq)+2OH^-(aq)\rightarrow ClO_2^{-}(aq)+ClO_3^{-}(aq)+H_2O(l)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of =

Rate in terms of appearance of =

The rate of disappearance of chlorine dioxide = $2.30\times 10^{-1} M/s$

$\frac{d[ClO_2]}{2dt}=\frac{d[ClO_2^{-}]}{dt}$

$\frac{2.30\times 10^{-1}}{2}=\frac{d[ClO_2^{-}]}{dt}$

$\frac{d[ClO_2^{-}]}{dt}=1.15\times 10^{-1}M/s$

The initial rate of appearance of chlorite ion under those same conditions is $
1.15\times 10^{-1}M/s$

Answer from: Quest

2b2t

explanation:

2b2t

Answer from: Quest

The answer is b because c don't explain why the moths are on them and it isn't a because as we know only one species of moth does this

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Chlorine dioxide reacts in basic water to form chlorite and chlorate according to the following chem...

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