The liquid 2-chloro-2,3-dimethylbutane has a density of 0.878 g/mL at 20.0°C. If a 138 gram sample of this compound is needed, what volume of the liquid at 20.0°C must be provided? volume= mL

157.2 mL

Explanation:

The following data were obtained from the question:

Density (D) of liquid = 0.878 g/mL

Mass (m) of liquid = 138 g

Volume (V) of liquid =.?

Density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, it is expressed as:

Density (D) = mass /volume

D = m/V

With the above formula, we can obtain the volume of the liquid as follow:

Density (D) of liquid = 0.878 g/mL

Mass (m) of liquid = 138 g

Volume (V) of liquid =.?

D = m/V

0.878 = 138/V

Cross multiply

0.878 × V = 138

Divide both side by 0.878

V = 138/0.878

V = 157.2 mL

Therefore, 157.2 mL of the liquid must be provided.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the answer is 303.15 or 303