You need to make an aqueous solution of 0.237 M chromium(III) acetate for an experiment in lab, using a 500 mL volumetric flask. How much solid chromium(III) acetate should you add

27.1 g of solid chromium(III) acetate should be added.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in ml

moles of =

Now put all the given values in the formula of molality, we get

Therefore, 27.1 g of solid chromium(III) acetate should be added.