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The answers to your questions are given below

Explanation:

1. KClO3 => Potassium trioxochlorate (V)

Thermal decomposition of KClO3.

When we heat potassium trioxochlorate (V), KClO3, it will slip into two producing potassium chloride, KCl and oxygen gas, O2 as shown below:

2KClO3(s) —> 2KCl(s) + 3O2(g)

Note: the above reaction will occur faster and at a lower temperature in the presence of manganese (iv) oxide as catalyst.

2a. Determination of the number protons and neutrons in Nitrogen–14.

Nitrogen–14 has the following:

Mass number = 14

Atomic number = 7

Proton =?

Neutron =?

Atomic number of an atom is simply the proton number. Therefore,

Proton = Atomic number

Atomic number = 7

Proton = Atomic number = 7

Proton = 7

Mass number = Proton + Neutron

Mass number = 14

Proton = 7

Neutron =?

14 = 7 + Neutron

Collect like terms

Neutron = 14 – 7

Neutron = 7

Therefore, Nitrogen–14 has 7 protons and 7 neutrons.

2b. Determination of the number protons and neutrons in Nitrogen–15.

Nitrogen–15 has the following:

Mass number = 15

Atomic number = 7

Proton =?

Neutron =?

Atomic number of an atom is simply the proton number. Therefore,

Proton = Atomic number

Atomic number = 7

Proton = Atomic number = 7

Proton = 7

Mass number = Proton + Neutron

Mass number = 15

Proton = 7

Neutron =?

15 = 7 + Neutron

Collect like terms

Neutron = 15 – 7

Neutron = 8

Therefore, Nitrogen–15 has 7 protons and 8 neutrons.

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