A reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. This is the equation of the reaction: Mg(ClO3)2 + 2NaOH → Mg(OH)2 + 2NaClO3.

Determine the theoretical amount of each product that the reaction will produce.

The reaction w
ill produce
2.72 moles
of magnesium hydroxide and
3.14 moles
of sodium chlorate.