72. A piece of unknown metal with mass 30 g is heated to 1100 C and dropped into 100.0 g of water at 200 C. The final temperature of the system is 25 degree Celsius. What is the specific heat of the metal

THE SPECIFIC HEAT OF THE METAL IS 28.69 J/g C

Explanation:

Mass of unknown metal = 30 g

Mass of water = 100 g

Initial Temperature of metal = 110 C

Initial temperature of water  = 200 C

Final temperature of the system = 25 C

Specific heat of water = 4200 J/ g C

Specific heat of metal = unknown

Heat lost = Heat gained\

M C Q = M C Q

30 * C * ( 25 - 110) = 100 * 4200 * (25 -200)

C = 100 * 4.18 * -175 / 30 * - 85

(the minus sign cancels out and we have):

C = 100 * 4.18 * 175 / 30 * 85

C = 73150 / 2550

C = 28.69 J/ g C

The specific heat of the unknown metal is hence 28.69 J/ g C

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being

m=9

step-by-step explanation: