QUESTION 4 What is the maximum pressure (in Torr) that will afford a N2 molecule a mean-free-path of at least 1.00 m at 25 oC

Maximum pressure P = 4.9 × 10⁻⁵ Pa

Explanation:

From the information given, the mean free path can be expressed with the formula:

Making Pressure P the subject of the formula because we intend to find the maximum pressure, we have:

At standard conditions

R = gas constant = 8.314 J/mol.K

T = temperature at 25°C = (273 + 25) = 298 K

π = pi = 3.14

d = (364× 10⁻¹²m)²

= avogadro's number = 6.023 × 10²³

λ = mean free path = 1.0 m

P = 0.007 kg/m.s²

P = 0.007 Pa

P = 4.9 × 10⁻⁵ Pa