Approximately how many moles of Al3 are reduced when 0.1 faraday of charge passes through a cell during the production of Al

HELLO YOUR QUESTION IS INCOMPLETE ATTACHED BELOW IS THE COMPLETE QUESTION

answer : 0.033 mol  ( A )

Explanation:

To determine the number of moles of AI3 that will be reduced when 0.1 Faraday passes through a cell during the production of AI

AI3+  + 3 e -------- AI  this means that it will take 3 mol to reduce AI3 to AI

1 mol AI = 3 F  electrons

therefore : 1 F electrons  = 1/3 mol of AI

therefore : 0.1 F ( Faraday ) = 0.1 * 1/3  = 0.033 mol of AI is needed

the answer is na (sodium)