How many grams of solid potassium chlorate (KClO 3, 122.55 g/mol) are needed to make 150 mL of 0.50 M solution

Explanation:

Hello,

In this case, since the molarity is defined as:

Whereas the volume of the solution is in liters, we first compute the moles of solute which in this case is the potassium chlorate:

Then, by using its molar mass of 122.55 g/mol, we compute the required mass as follows:

Regards.

he would use the colour black