What is the free energy change in kJ/mol for the process below at 43.9 °C when the concentration of A =0.88 M, B = 0.49 M and C = 0.69 M? g

-15.5 kJ/mol

Explanation:

2A ⇄ 2B + C

   =

  = 0.21

T = C

   = (273 + 43.9) K  =  316.9 K

kJ/mol

R = 8.314 J/k-mol  =  0.008314 kJ/k-mol

     = -15.5 kJ/ mol

what are the choices?

yes they ca   is ur ansswerrr