Chemistry, 01.09.2020 21:01 Candieboo6939
How many ml of 0.213-M Na3PO4 are required to deliver 66.4 mmol Na1+ ions?
Answers: 1
, M = 0.213 M .
.![V=[\text{ 66.4 mmol of }Na^+] + [\dfrac{\text{1 mm of }Na_3PO_4}{\text{3 mmol of }Na^+}]+[\dfrac{\text{1 ml }Na_3PO_4}{\text{0.213 mmol of }Na_3PO_4}]](/tpl/images/0737/0379/c56e8.png)
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