A florist prepares a solution of nitrogen-phosphorus fertilizer by dissolving 5.66 g of NH4NO3 and 4.42 g of (NH4)3PO4 in enough water to make 17.0 L solution. What is the molarity of NH4+ in the solution?

9.39x10⁻³M NH₄⁺

Explanation:

To find molarity of NH₄⁺ we need to calculate moles of NH₄⁺ that comes from NH₄NO₃ and (NH₄)₃PO₄

Moles from NH₄NO₃ (Molar mass: 80.043g/mol):

5.66g * (1mol / 80.043g) = 0.0707 moles NH₄NO₃ = Moles NH₄⁺

Moles from (NH₄)₃PO₄ (Molar mass: 149.09g/mol):

4.42g * (1mol / 149.09g)  = 0.0296 moles (NH₄)₃PO₄ * 3 = 0.0889 moles NH₄⁺

Total moles NH₄⁺:

0.0707 moles + 0.0889 moles = 0.1596 moles NH₄⁺ in 17.0L

Molarity: 0.1596 moles / 17.0L =

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