A saline solution contains 0.800 g of NaCl (molar mass 58.55 g/mol) in 54.6 mL of solution. Calculate the concentration of NaCl in this solution, in units of molarity Express the concentration in molarity to three significant figures.

0.25 M

Explanation:

Data obtained from the question include:

Molar mass of NaCl = 58.55 g/mol

Mass of NaCl = 0.800 g

Volume = 54.6 mL

Next, we shall determine the number of mole in 0.800 g of NaCl. This can be obtained as follow:

Molar mass of NaCl = 58.55 g/mol

Mass of NaCl = 0.800 g

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 0.8/58.55

Mole of NaCl = 0.0137 mole

Next, we shall convert 54.6 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

54.6 mL = 54.6 /1000

54.6 mL = 0.0546 L

Finally, we shall determine the molarity of the solution as follow:

Mole of NaCl = 0.0137 mole

Volume = 0.0546 L

Molarity =?

Mol= mole /Volume

Molarity = 0.0137/0.0546

Molarity = 0.25M

Therefore, the molarity of the solution is 0.25 M

your answer is c) plasma

~*"auba14"*~

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.