Calculate the molar free energy of combustion for liquid n-octane, C8H18 with the given data: AG'CH,,!) 6.4 kJ/mol AG®(00,,8) -394.4 kJ/mol AGʻ(H,0,8) -228.57 kJ/mol a. -5218.7 kJ/mol b. -5384.6 kJ/mol c. -629.4 kJ/mol d. +629.4 kJ/mol e. -2609.4 kJ/mol

a. -5218.7 kJ/mol

Explanation:

Hello,

In this case, the combustion of liquid n-octane is represented by:

Thus, the molar free energy of combustion (reaction) is:

Hence, with the given data we obtain:

Therefore, answer is a. -52 kJ/mol18.7.

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yes yes yes yes yes yes yes yes yes yes yes yes yes yes yes

explanation:

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.