What is the mass of a sample of iron that has had 300.0 j applied to it and heats up from 20.0 degrees Celsius to 40.0 degrees Celsius.. the specific heat of iron is 0.46j/gC

The mass of a sample of iron that has had 300 J applied to it and heats up from 20 degrees Celsius to 40 degrees Celsius is 32.61 grams.

Explanation:

Calorimetry is the measurement and calculation of the measurement of heat changes exchanged by a body or a system produced in physical and chemical processes.

The sensible heat of a body is the amount of heat received or transferred by a body to produce a change in temperature but without a change in physical state.

The sensible heat in a constant pressure is calculated by:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c, and where ΔT is the temperature variation (ΔT=Tfinal - Tinitial)

In this case:

Replacing:

300 J= 0.46 * m* (40 - 20) C

Solving:

300 J= 0.46 * m* 20 C

m= 32.61 g

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :