How many moles of NaOH are present in 65.00 g of NaOH(s)? *

Explanation:

To find the number of moles we must first find the molar mass of the compound after that we use the formula

where

n is the number of moles

M is the molar mass

m is the mass

M(Na) = 23 , M(O) = 16 , M(H) = 1

Molar mass ( NaOH ) = 23+ 16 + 1

= 40 g/mol

mass = 65 g

Substitute the values into the above formula and solve

That's

We have the final answer as

Hope this helps you

the answer for sodium is 0.186

the answer for rubidium is 0.251

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