Given 6.05 grams of NH₃, how many moles of N₂ would be produced? *

3.025 mol N₂

Explanation:

2 NH₃  ⇆  N₂  +  3 H₂

This is the reaction that decomposes NH₃.  Use the mole ratios to solve.  For every 2 moles of NH₃ that are consumed, 1 mole of N₂ is produced.

(6.05 mol NH₃) × (1 mol N₂/2 mol NH₃) = 3.025 mol N₂

You will produce 3.025 moles of N₂.