The bf3 molecule is planar. the attachment of a fluoride ion to the boron in bf3 through a coordinate covalent bond, creates the bf4 ion. what is the geometric shape of this ion?

The geometry of BF₄⁻ anion is tetrahedral

Explanation:

According to the Valence Bond Theory, the boron atom in BF₃ molecule is sp² hybridized. As one 2s and two 2p orbitals hybridize to form three sp² hybrid orbitals.

Therefore, the molecular geometry of BF₃ molecule is trigonal planar.

However, in a BF₄⁻ ion, the boron atom is sp³ hybridized. As it forms four sp³ hybrid orbitals by hybridization of one 2s and three 2p orbitals.

Therefore, the molecular geometry of BF₄⁻ anion is tetrahedral.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa