Chemistry, 20.09.2020 04:01 QueenNerdy889

2. Report each of the following quantities to 3 significant figures. Use standard notation if possible, or exponential notation if standard notation won't work.
a. 86,942
f. 56,018
b. 0.00621875
g. 0.003870
c. 107062.03
h. 15.9994
d. 4.00049
i. 12.011
e. 96
j. 2,000

Answers: 3

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Answer from: UltimateGoal

a. 86,942 = 8.69x10⁴

f. 56,018 = 5.60x10⁴

b. 0.00621875 = 6.22x10⁻³

g. 0.003870 = 3.87x10⁻³

c. 107062.03 = 1.07x10⁵

h. 15.9994 = 16.0

d. 4.00049 = 4.00

i. 12.011 = 12.0

e. 96 = 9.60x10¹

j. 2,000 = 2.00x10³

Explanation:

Hello,

In this case, rounding off each measurement to three significant figures, considering that if the fourth figure is five or more, the third one is rounded, we obtain:

a. 86,942 = 8.69x10⁴ (four places until the last digit and third digit is not rounded).

f. 56,018 = 5.60x10⁴ (four places until the last digit and third digit is not rounded).

b. 0.00621875 = 6.22x10⁻³ (three places until the first digit and third digit is rounded).

g. 0.003870 = 3.87x10⁻³ (three places until the first digit and third digit is not rounded).

c. 107062.03 = 1.07x10⁵ (five places until the last non-decimal digit and third digit is not rounded).

h. 15.9994 = 16.0 (those consecutive nines round the number to 16.0).

d. 4.00049 = 4.00

i. 12.011 = 12.0

e. 96 = 9.60x10¹ (exponential notation is needed since the number initially has two significant figures so an additional zero is added)

j. 2,000 = 2.00x10³ (three places until the last digit and third digit is not rounded).

Best regards.

Answer from: Quest

Ithink d hope that

Answer from: Quest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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2. Report each of the following quantities to 3 significant figures. Use standard notation if possib...

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