There are two compounds of titanium and chlorine. One compound contains 31.04 % titanium by mass, and the other contains 74.76 % chlorine by mass. What are the ratios of titanium and chlorine atoms in the second compound? please help :(

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we have two compounds of titanium and chlorine for both of them. Were going to assume 100 Grimm's for compounds one. We're told that we have 31.0% titanium, 31.0 4%. So in 100 grams would be 31.4 grams of titanium and subtracting form. 100 would be bust with 68 point 96 grams of chlorine. Come back to that in a moment in compound to we're told that we have 74.76 percent. So so in 100 grams there'll be 74.76 grams of chlorine 100. Minus 74.76 would leave us with 25 0.24 grams of titanium. Let's convert. Both of these two moles will start with Compound one. Titanium has a molar mass of 47.9 grams. Promote chlorine 35.5 grams promote 31.4 divided by 47.9. Would be 0.6 648 moles and 60.96 divided by 35.5. Would be 1.9 formals. Gonna divide by 0.648 Give me one and 2.997 closest whole numbers. Three. This would be a 1 to 3 ratio for the first compound for the second compounds, so give me 0.5 to 7 rules of titanium and 2.106 moles of chlorine. Divide by 0.5 to 7 would give me one ends 3.996 or closest Whole numbers. Four compounds. He would be a 1 to 4 ratio of titanium to chlorine.

Explanation:

One compound contains 31.04% titanium by mass, and the other contains 74.76% ... What are the ratios of titanium and chlorine atoms in the two compounds?

it should be p1 v1 = p2 v2