Chemistry, 20.09.2020 15:01 smithsavannah295
olecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1. (a) What is the half-life for this reaction? s (b) If you start with 0.048 M I2 at this temperature, how much will remain after 5.37 s assuming that the iodine atoms do not recombine to form I2? M
Answers: 3
![[I_2]=0.011M](/tpl/images/0771/9802/19391.png)
![[I_2]=[I_2]_0exp(-kt)](/tpl/images/0771/9802/e9e96.png)
![[I_2]=0.048Mexp(-0.271s^{-1}*5.37s)\\\\](/tpl/images/0771/9802/4a6e2.png)
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olecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0...
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