The distance between two bonded atoms (the bond length), is usually in units of picometers, where 1.00 m = 1.00 x 1012 pm (or 1.00 pm = 1.00 x 10-12 m). What is the distance between two carbon atoms, in units of miles, if the bond length is 121 pm?

7.52 × 10⁻¹⁴ mi

Explanation:

Step 1: Given data

Bond length between two carbon atoms (l): 121 pm

Step 2: Convert "l" to meters

We will use the conversion factor 1.00 m = 1.00 × 10¹² pm.

121 pm × (1.00 m / 1.00 × 10¹² pm) = 1.21 × 10⁻¹⁰ m

Step 3: Convert "l" to miles

We will use the conversion factor 1.00 mi = 1609.34 m.

1.21 × 10⁻¹⁰ m × (1.00 mi / 1609.34 m) = 7.52 × 10⁻¹⁴ mi

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2