The volume of water in a transfer pipette is 15.23 mL. A 6.7 mL volume of water with them transfer it out. Considering significant figures what is the new volume?

8.5mL

Explanation:

According to the question, a transfer pipette contains 15.23 mL of water. 6.7 mL of water is drawn out of it, this will give :

= 15.23 - 6.7

= 8.53

However, observing the measurements, 15.33mL, which is the initial volume of water in the transfer pipette has 4 significant figures (4 s.f) while the final volume after transference is 6.7 mL, which is in 2 significant figures.

In addition/subtraction, the digit with the lowest number of significant figures will determine the outcome it result.

Hence, 8.53 (3 s.f) will be reported as 8.5 (2 s.f).

Therefore, the final volume is 8.5 mL

it should be p1 v1 = p2 v2

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